The upper and lower edges of the horizontal wire are the same size, and the two rows are wider than the upper and lower edges of the wire.
You give "the vertical width is 4cm" and the width of the upper and lower sides is set to Acm, so the perimeter of the horizontal graph is:
2(Xcm+2×4cm+2×2cm+Ycm+2×Acm+2×2cm)= 2Xcm+2 Ycm+4 Acm+32cm
The two vertical silk edges are the same, and the zenith is slightly larger than the field.
You give "the vertical width is 4cm", and the widths of the upper and lower sides are set to Acm and Bcm respectively, so the circumference of the vertical width is:
2(Ycm+2×4cm+2×2cm+Xcm+Acm+Bcm+2×2cm)= 2x cm+2 Ycm+2 Acm+2 Bcm+32cm