The number of people participating in the choir accounts for three fifths of the total number. How many students are there in the two groups?
think
The key to solve this problem is to find the equivalence relation.
Several sixth-grade students joined the calligraphy group and the chorus.
get
Total number of sixth-grade students = number of people participating in calligraphy group+number of people participating in chorus group.
So there is
Number of participants in calligraphy group = total number of sixth grade-number of participants in chorus group.
Let the total number of sixth grade students be X.
According to the number of people participating in the choir, it accounts for three-fifths of the total number.
The number of people participating in the choir is: (3/5) x.
Therefore, the number of participants in the calligraphy group is: X-(3/5) X.
Moreover, the number of people participating in the calligraphy group accounts for one third of the total number, which is more than 10.
The number of participants in the calligraphy group is (1/3)x+ 10.
Through the equivalence relation:
Number of participants in calligraphy group = number of participants in calligraphy group.
Equation: x-(3/5) x = (1/3) x+10.
By solving the equations, we can know how many students have participated in these two groups.
Solution: let the total number of sixth grade students be X.
According to the meaning of the question
x-(3/5)x=( 1/3)x+ 10。
solve an equation
x= 150。
So there are 150 students in these two groups.
When water becomes ice, its volume increases by one tenth. What is the volume of a piece of ice with a volume of 143 square decimeter after it becomes water?
When water freezes, its volume increases by one tenth.
Correspondingly, there is also
When ice becomes water, its volume is reduced by one tenth.
therefore
The volume of ice into water = the volume of ice-the volume of ice * one tenth.
Solution: When water turns into ice, its volume increases by one tenth.
After freezing into water, the volume is reduced by one tenth.
therefore
The volume after freezing into water = 143- 143* one tenth.
= 143- 14.3
= 128.7 (m3)
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