(1) substitution reaction
(2)
(3)
(4)
(5) New hydrogen production of sodium hydroxide solution and copper oxide suspension.
Analysis of test questio
(1) substitution reaction
(2)
(3)
(4)
(5) New hydrogen production of sodium hydroxide solution and copper oxide suspension.
Analysis of test questions: (1) The carboxylic acids conforming to the molecular formula A are CH 3 CH 2 CH 2 COOH and (ch3) 2ccooh. Analogous or imitating the known reaction, the former can generate ch3ch2chclccooh or ch3clcch2cooh through substitution reaction, and the latter can generate (ch3) 2ccclcooh through substitution reaction. Ch3ch2chclcoooh, ch3clch2cooh and (ch3) 2ccclcooh contain four, four and two kinds of hydrogen atoms, respectively. According to the meaning of the question, if B is (CH3) 2ccclcooh, then A is (CH3) 2ccclcooh; 2 (CH3) 2chcooh+2na → 2 (CH3) 2chcoona+H2 ↑, then 0. 1molA reacts with enough na to generate 0.05mol H 2, and v (H2) = 0.05mol× 22.4l/mol =1./kloc-0. (2) Inferring from the structural changes before and after the substance transformation, the purpose of I is to prepare bromobenzene, and then benzene and liquid bromine undergo substitution reaction under the catalysis of iron or iron bromide to generate bromobenzene and hydrogen bromide; (3) ellipsis; (4) According to the reaction conditions, C is CH 2 =C(CH 3 )COOH, D is CH 2 = C (CH 3) COOH 3, and E is C6H5CH = C (CH3) COOH 3; (5) The molecular formula of F is C 4 H 8 O 2. According to the reaction conditions and the structural formula of the product, if the backward push and the forward push are combined, the F with elimination reaction is HOCH 2 CH(CH 3 )CHO, and the C with catalytic oxidation reaction is CH 2 =C(CH 3 )COOH. The essence of judging whether the reaction ⅲ is complete is to judge whether it contains aldehyde groups. Therefore, NaOH solution should be selected to neutralize CH _ 2 = C (CH _ 3) COOH. After the solution is alkaline, new copper oxide suspension or silver ammonia solution for hydrogen production should be added, and then heated. If red precipitate or silver mirror is produced, it means that aldehyde group still exists, which means that the reaction III is not complete, and vice versa.