② If the "head" is 6, 1 is taken for "lifting" and 2 is taken for "low", there is 16×3=48, but the remaining numbers cannot form the second equation. It is verified that "head" can only be 4, and "low" cannot be 2. If you can only take 3, then 34×2=68, leaving 1, 5, 7, 9, 0, because the existing "head" is 4, so 14×5=70.
That is, 1 equals 90=45×2.
2 is 14×5=70.