∴∠DAC=∠DCA=30,
∴∠ACB=30,
∴∠BAC=90,
∴tan∠ACB= exchange company,
∴AC= 2 3 3 = 2 3,
So the answer is: 2 3;
(2) As shown in the figure, if point A is the symmetrical point A' about MN, then A' is on ⊙O,
When BP ′+AP ′ is minimum, connect Ba ′ intersection MN at P ′.
According to symmetry, AP ′ = a ′ p ′,
∴bp′+ap′=bp′+a′p′=a′b,
Connect OA, OB, OA',
It is known that arc AN= arc A'n,
Then ∠ NOA' = ∠ NOA = 2 ∠ m = 60,
Point b is that midpoint of arc AN,
∴∠BON=30
∴∠boa′=90
And MN= 1,
∴ in RT △ OA ′ b, A ′ b = 22.
That is, the minimum value of BP+AP is 2 2.
(3) ① The symmetry axis y of ∫ parabola = AX2+BX+C (A ≠ 0) is x= 1, and the parabola passes through A (- 1, 0).
C(0, -3) two points, respectively, into the second resolution function:
∴ - b 2a = 1 a-b+c=0 c=-3,
Solution: a= 1, b=-2, c=-3,
The quadratic resolution function is y=x 2 -2x-3,
② Get the straight line BC: y = x-3,
∴M( 1, -2), the length of AC is: 10.
∴△△△ The minimum perimeter of ACM is the minimum value of AM+CM.
∫AM+CM = BC = 3 ^ 2,
∴△△△ The minimum circumference of ACM is: 10+32.